wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two resistances 500ohm and 1000ohm are connected in series with a battery of 1.5volt. The voltage across the 1000ohm resistances is measured by a voltmeter having a resistance of 1000ohm. The reading in the voltmeter would be then:

373591_bffc29cd21584caa821cb3c4fa88efbe.png

A
1.5 Volt
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.0 Volt
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.75 Volt
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
0.50 Volt
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 0.75 Volt
The equivalent resistance of the Voltmeter (1000Ω) and the given resistance of 1000Ω is 500ohms.

Now in effect there are two resistance in the circuit each of 500Ω.
Hence the p.d. of 1.5volt will be equally divided across the two i.e., p.d. across each will be 0.75volt.
The voltmeter will read this potential difference.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Cell and Cell Combinations
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon