Two resistances are connected in series as shown in the diagram. What is the current through $R$ ?

1 A

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2 A

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3 A

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4 A

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Solution

The correct option is B $2 A$
The voltage across $5 Ω$ resistor is $V = 10 V$

Current,
$I = \frac{V}{R}$ ; according to ohm' law

$\Rightarrow I = \frac{10}{5}$

$\Rightarrow I = 2 A$

Since resistance $5 Ω$ and $R$ are in series and hence current through both resistance is the same.
Hence current through $R$ is also $2 A$ .

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Two resistances are connected in series as shown in the diagram. What is the current through R?

The correct option is B 2A The voltage across 5Ω resistor is V=10VCurrent, I=VR; according to ohm' law⇒I=105⇒I=2ASince resistance 5Ω and R are in series and hence current through both resistance is the same.Hence current through R is also 2A.

Two resistances are connected in series as shown in the diagram. What is the current through $R$ ?