Two resistances R 1 and R 2 provide series to parallel equivalents as n -1- Then the correct relationship isA- R 1- R 22- R 2- R 12- n 2B- R 1- R 23 - 2- R 2- R 13 - 2- n 3 - 2C- R1-R2-R2-R1-nD- R 1- R 21 - 2- R 2- R 11 - 2- n 1 - 2

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Series and Parallel Combination of Resistors

Two resistanc...

Question

Two resistances $R_{1}$ and $R_{2}$ provide series to parallel equivalents as $\frac{n}{1}$ . Then the correct relationship is

{(\frac{R_{1}}{R_{2}})}^{2} + {(\frac{R_{2}}{R_{1}})}^{2} = n^{2}

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{(\frac{R_{1}}{R_{2}})}^{3 / 2} + {(\frac{R_{2}}{R_{1}})}^{3 / 2} = n^{3 / 2}

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(\frac{R_{1}}{R_{2}}) + (\frac{R_{2}}{R_{1}}) = n

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{(\frac{R_{1}}{R_{2}})}^{1 / 2} + {(\frac{R_{2}}{R_{1}})}^{1 / 2} = n^{1 / 2}

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T_{1}, T_{2} a n d r_{1}, r_{2}

\frac{T_{1}}{T_{2}}

If the sum of the areas of two circles with radii R₁ and R₂ is equal to the area of a circle of radius R, then

R_{1}

R_{2}

\frac{n}{1}

r_{1}, r_{2}, r_{1}^{'}

r_{2}^{'}

Let $c_{1} & c_{2}$ be the centers and $r_{1} & r_{2}$ be the radius of two circles. Then

Cases Conditions

p. 1. $| r_{1} - r_{2} | < c_{1} c_{2} < r_{1} + r_{2}$

q. 2. $| r_{1} - r_{2} | = c_{1} c_{2}$

r. 3. $c_{1} c_{2} < | r_{1} + r_{2} |$

4. $r_{1} + r_{2} < c_{1} r_{2}$

t. 5. $r_{1} + r_{2} = c_{1} r_{2}$

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