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Question

Two resistors 2 Ω and 5 Ω are connected in series with a 7 V battery. Find the potential difference across the 5 Ω resistor.


A

2 V

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B

7 V

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C

5 V

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D

1 V

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Solution

The correct option is C

5 V


For series connection, effective resistance in the circuit is given by:
R=R1+R2
Total resistance in circuit, R=2 Ω+5 Ω=7 Ω

The amount of current through the effective resistance when connected to 7 V battery:

I=VR (ohm's law)


I=7 V7 Ω=1 A

The current through each resistance is same in the series circuit. Hence, potential drop across 5 Ω resistor is given by,
V=1 A×5 Ω
V=5 V


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