Two resistors $2 Ω$ and $5 Ω$ are connected in series with a $7 V$ battery. Find the potential difference across the $5 Ω$ resistor.

$2 V$

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$7 V$

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$5 V$

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$1 V$

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Solution

The correct option is C
$5 V$

For series connection, effective resistance in the circuit is given by:
$R = R_{1} + R_{2}$
$∴$ Total resistance in circuit, $R = 2 Ω + 5 Ω = 7 Ω$

The amount of current through the effective resistance when connected to $7 V$ battery:

$I = \frac{V}{R}$ (ohm's law)

$I = \frac{7 V}{7 Ω} = 1 A$

The current through each resistance is same in the series circuit. Hence, potential drop across $5 Ω$ resistor is given by,
$V = 1 A \times 5 Ω$
$V = 5 V$

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