Two resistors have their resistances in the ratio $2 : 3.$ If these two resistors are connected in parallel, then the ratio of respective power dissipated through the resistors will be equal to

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3 : 2

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1 : 3

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5 : 6

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4 : 9

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Solution

The correct option is A $3 : 2$
In parallel combination, the voltage across resistors remain same
Power dissipated $= \frac{V^{2}}{R}$

$\Rightarrow Power \propto \frac{1}{R}$

Given, $\frac{R_{2}}{R_{1}} = \frac{3}{2}$

$∴ \frac{P_{1}}{P_{2}} = \frac{R_{2}}{R_{1}} = \frac{3}{2}$

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Two resistors have their resistances in the ratio 2:3. If these two resistors are connected in parallel, then the ratio of respective power dissipated through the resistors will be equal to [0.77 Mark]

The correct option is A 3:2In parallel combination, the voltage across resistors remain same Power dissipated =V2R ⇒Power∝1R Given, R2R1=32 ∴P1P2=R2R1=32

Two resistors have their resistances in the ratio $2 : 3.$ If these two resistors are connected in parallel, then the ratio of respective power dissipated through the resistors will be equal to

$[$ 0.77 Mark $]$

The correct option is A $3 : 2$
In parallel combination, the voltage across resistors remain same
Power dissipated $= \frac{V^{2}}{R}$

$\Rightarrow Power \propto \frac{1}{R}$

Given, $\frac{R_{2}}{R_{1}} = \frac{3}{2}$

$∴ \frac{P_{1}}{P_{2}} = \frac{R_{2}}{R_{1}} = \frac{3}{2}$