Question

Two resistors of resistance 2R and 3R are connected in series with a battery, which has an emf of E and an internal resistance R. What is the potential difference across the resistor of resistance 2R?

• A. 2E/5
• B. E/2
• C. E/3
• D. 2E

Answer 1

The correct option is C

E/3

Here, total resistance of the circuit = 2R+3R+R = 6R

Total emf = E

Hence, total current in the circuit = E/6R

Therefore, voltage across 2R resistor = (E/6R) x 2R = E/3