You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Parallel Combination

Two resistors...

Question

Two resistors of resistance $4 Ω$ and $6 Ω$ are connected in parallel to a cell to draw 0.5 A current from the cell. What is current through resistor $4 Ω$ ?

0.3 A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.5 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.2 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.2 A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 0.3 A
In a parallel resistance system current in 1st branch =
$I_{1} = (\frac{R_{2}}{R_{1} + R_{2}}) \times I$
$I_{1} = \frac{6}{4 + 6} \times 0.5$
$I_{1} = \frac{3}{10} = 0.3 A$

Suggest Corrections

Similar questions

Q. Two resistors of

4 Ω

and

6 Ω

are connected in parallel to a cell to draw

0.5 A

current from the cell.
Draw a labelled circuit diagram showing the above arrangement

Q. Two Resistor

2 Ω

and

4 Ω

are connected in parallel. Two more Resistor

3 Ω

and

6 Ω

are connected in parallel. These two combinations are in series with a battery of emf

5 V

and internal Resistance

0.7 Ω

. Calculate the current through

6 Ω

Resistors.

Q. A battery of emf

12 V

and internal resistance

2 Ω

is connected with two resistors A and B of resistance

4 Ω

and

6 Ω

respectively joined in series.
Find:
(i) Current in the circuit.
(ii) The terminal voltage of the cell.
(iii) The potential difference across

6 Ω

Resistor.
(iv) Electrical energy spent per minute in

4 Ω

Resistor.

Two resistors having resistance $4 Ω$ and $6 Ω$ are connected in parallel. Find their equivalent resistance.

A 12 W resistor is connected in series with a cell of emf 1.5 V and negligible internal resistance (or terminal voltage 1.5 V). How must a 4 W resistor be introduced in the circuit, so that the current drawn from the cell is 0.5 A?

Join BYJU'S Learning Program

Two resistors of resistance 4Ω and 6Ω are connected in parallel to a cell to draw 0.5 A current from the cell. What is current through resistor 4Ω ?

The correct option is A 0.3 AIn a parallel resistance system current in 1st branch = I1=(R2R1+R2)×II1=64+6×0.5I1=310=0.3A

Two resistors of resistance $4 Ω$ and $6 Ω$ are connected in parallel to a cell to draw 0.5 A current from the cell. What is current through resistor $4 Ω$ ?

The correct option is A 0.3 A
In a parallel resistance system current in 1st branch =
$I_{1} = (\frac{R_{2}}{R_{1} + R_{2}}) \times I$
$I_{1} = \frac{6}{4 + 6} \times 0.5$
$I_{1} = \frac{3}{10} = 0.3 A$