Question

Two resistors of resistance $4\Omega$ and $6\Omega$ are connected in parallel to a cell to draw $0.5A$ current from the cell. What is the current through resistor $6\Omega$?

• A. $0.2A$
• B. $0.5A$
• C. $2.4A$
• D. $1.2A$

Answer 1

The correct option is A $0.2A$

Two resistors of resistance $4\Omega$ and $6\Omega$ are connected in parallel.

Hence, equivalent resistance in parallel is given by,

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}$

$\Rightarrow \frac{1}{R_{eq}}=\frac{1}{4}+\frac{1}{6}=\frac{10}{24}$

$\Rightarrow R_{eq}=\frac{24}{10}=2.4\Omega$

Using Ohm's law, $V=iR$

$V=0.5\times 2.4=1.2V$

Since, value of voltage is same for objects connected in parallel, Hence, voltage drop across $6\Omega$ resistor is also $1.2V$

Hence, using Ohm's law , Current through resistor $6\Omega$:

$1.2=i\times 6$

$i=0.2A$