Two resistors of resistances 4 - each are connected in series- Find the equivalent resistance of the circuit-

The correct option is C 8 Ω Since the resistors nbsp;R_1 amp;R_2 are in series, the effective resistance of the circuit is given by: R_eff =R_1 +R_2 nbs ...

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Byju's Answer

Standard X

Physics

Equivalent Resistance of a System of Resistor

Two resistors...

Question

Two resistors of resistances $4 Ω$ each are connected in series. Find the equivalent resistance of the circuit.

$8 Ω$

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$2 Ω$

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$4 Ω$

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$1 Ω$

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Solution

The correct option is A
$8 Ω$

Since the resistors $R_{1}$ & $R_{2}$ are in series, the effective resistance of the circuit is given by:
$R_{e f f}$ = $R_{1}$ + $R_{2}$
Given: $R_{1}$ = $R_{2} = 4 Ω$
$∴ R_{e f f} = 4 Ω + 4 Ω$
$\Rightarrow R_{e f f} = 8 Ω$

Suggest Corrections

Two resistors of resistances 4 Ω each are connected in series. Find the equivalent resistance of the circuit.

The correct option is A 8 Ω Since the resistors R1 &R2 are in series, the effective resistance of the circuit is given by: Reff =R1 +R2 Given: R1 = R2=4Ω ∴Reff=4Ω+4Ω ⇒Reff=8Ω

Two resistors of resistances $4 Ω$ each are connected in series. Find the equivalent resistance of the circuit.

The correct option is A
$8 Ω$

Since the resistors $R_{1}$ & $R_{2}$ are in series, the effective resistance of the circuit is given by:
$R_{e f f}$ = $R_{1}$ + $R_{2}$
Given: $R_{1}$ = $R_{2} = 4 Ω$
$∴ R_{e f f} = 4 Ω + 4 Ω$
$\Rightarrow R_{e f f} = 8 Ω$