Two resistors of resistances R1 = (300 ± 3) Ω and R2 = (500 ± 4) Ω are connected in series. The equivalent resistance of the series combination is
A
(800 ± 1) Ω
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B
(800 ± 7) Ω
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C
(200 ± 7) Ω
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D
(200 ± 1) Ω
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Solution
The correct option is B (800 ± 7) Ω The equivalent resistance of series combination is Rs=R1+R2=300Ω+500Ω=800Ω The error in equivalent resistance is given by ΔR=(ΔR1+ΔR2)=(3+4)Ω=7Ω Hence, the equivalent resistance along with error is (800±7)Ω.