Two resistors of resistor 2 - and 5 - are connected in series with a 7 v battery-A- 2 VB- 7 VC- 5 VD- 1 V

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Byju's Answer

Standard IX

Physics

Ohm's Law

Two resistors...

Question

Two resistors of resistor 2Ω and 5Ω are connected in series with a 7v battery.

2 V

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7 V

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5 V

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1 V

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Solution

The correct options are
A
2 V

C
5 V

Total resistance in circuit = 2 + 5 = 7 (series connection)

Using ohm's law to find net current,

V = IR

7 = I $\times$ 7

I = 1A

Potential drop across 5Ω resistor

⇒ V = IR

V = 1 $\times$ 5

V = 5Ω

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Two resistors of resistor 2Ω and 5Ω are connected in series with a 7v battery.

The correct options are A 2 V C 5 V Total resistance in circuit = 2 + 5 = 7 (series connection) Using ohm's law to find net current, V = IR 7 = I × 7 I = 1A Potential drop across 5Ω resistor ⇒ V = IR V = 1 × 5 V = 5Ω

The correct options are
A
2 V

C
5 V

Total resistance in circuit = 2 + 5 = 7 (series connection)

Using ohm's law to find net current,

V = IR

7 = I $\times$ 7

I = 1A

Potential drop across 5Ω resistor

⇒ V = IR

V = 1 $\times$ 5

V = 5Ω