Two resistors of resistor 2Ω and 5Ω are connected in series with a 7v battery. Find the potential difference across the 5Ω resistor.
5v
Total resistance in circuit = 2 + 5 = 7
(since in series)
Using ohm’s law to find net current
V = IR
7 = I*7
I = 1A
Potential drop across 5Ω resistor
⇒ V = IR
V = 1 × 5
V = 5Ω