Two resistors of resistor 2Ω and 5Ω are connected in series with a 7V battery. Find the potential difference across the 5Ω resistor.
5 V
Total resistance in circuit = 2 + 5 = 7Ω (series connection)
Using ohm's law to find net current,
V = IR
7 = I × 7
I = 1A
Potential drop across 5Ω resistor
⇒ V = IR
V = 1 × 5
V = 5 V