Two resistors R1(24±0.5)Ω and R2(8±0.3)Ω are joined in series. The equivalent resistance is
R1 = 24 ± 0.5
R2 = 8 ± 0.3
In series R1 + R2 = 32 ± 0.8
A battery of 12V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.5 Ω and 5 Ω. How much current would flow through the 5-Ω resistor?