Two resistors $R_{1} = 60 Ω$ and $R_{2} = 90 Ω$ are connected in parallel. If electric power consumed by the resistor $R_{1}$ is $15$ W, calculate the power consumed by the resistor $R_{2}$ .

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Solution

Electric power consumed by $R_{1}$ is $P_{1} = 15$ W
Potential difference across resistor $R_{1}$ $V = \sqrt{P_{1} R}$
$∴$ $V = \sqrt{(15) (60)} = 30$ volts
Since both resistors are connected in parallel, thus potential difference across resistor $R_{2}$ is also $V = 30$ volts
Thus power consumed by resistor $R_{2}$ is $P_{2} = \frac{V^{2}}{R_{2}}$
$∴$ $P_{2} = \frac{(30)^{2}}{90} = 10$ W

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Two resistors R1=60Ω and R2=90Ω are connected in parallel. If electric power consumed by the resistor R1 is 15W, calculate the power consumed by the resistor R2.

Electric power consumed by R1 is P1=15 WPotential difference across resistor R1 V=√P1R∴ V=√(15)(60)=30 voltsSince both resistors are connected in parallel, thus potential difference across resistor R2 is also V=30 voltsThus power consumed by resistor R2 is P2=V2R2∴ P2=(30)290=10 W

Two resistors $R_{1} = 60 Ω$ and $R_{2} = 90 Ω$ are connected in parallel. If electric power consumed by the resistor $R_{1}$ is $15$ W, calculate the power consumed by the resistor $R_{2}$ .