Two resistors, $R_{1}$ and $R_{2}$ are connected in series. If the current through the resistor $R_{1}$ is $2 A$ and the power dissipated in the resistor $R_{2}$ is $10 W,$ then the value of resistance of the resistor $R_{2}$ is

3.9 Ω

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1.9 Ω

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4 Ω

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2. 5 Ω

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Solution

The correct option is D $2. 5 Ω$
In series combination, current through both resistors will be equal.

Power dissipated by a resistor is given by,

$P = I^{2} R$

For resistor $R_{2}$ ,

$10 = 2^{2} \times R_{2}$

$\Rightarrow R_{2} = \frac{10}{4} = 2.5 Ω$

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