CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two resistors R1 and R2 may be connected either in series or in parallel across a battery of zero internal resistance. It is required that the joule heating for parallel combination be five times that for series combination. If R1=100Ω, find possible values of R2.

A
38.2Ω
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
35.3Ω
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
48.2Ω
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
261.8Ω
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
A 38.2Ω
D 261.8Ω
Equivalent resistance for parallel connection Rp=100R2100+R2
Equivalent resistance for series connection Rs=100+R2
Joule heat produced H=V2tR H1R
Hp=5Hs 1Rp=5Rs
100+R2100R2=5100+R2
OR R22300R2+10000=0
R2=38.2Ω or 261.8Ω

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Heating Effects of Electric Current
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon