Two rigid objects A, B of same dimensions are applied with forces in the ratio 4 : 9 respectively. If the perpendicular distance of the force from the axis of rotation of two objects is same then turning force is greater in which body?

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Solution

Turning force (Torque)= Force $\times$ Perpendicular distance of the force from the axis of rotation
Since perpendicular distance are same so turning force is depend on forces.
$∴$ T $_{A}$ : T $_{B}$ = 4:9
So Turning Force is greater in body B.

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Two rigid objects A, B of same dimensions are applied with forces in the ratio 4 : 9 respectively. If the perpendicular distance of the force from the axis of rotation of two objects is same then turning force is greater in which body?

Turning force (Torque)= Force × Perpendicular distance of the force from the axis of rotationSince perpendicular distance are same so turning force is depend on forces.∴ TA: TB = 4:9 So Turning Force is greater in body B.

Turning force (Torque)= Force $\times$ Perpendicular distance of the force from the axis of rotation
Since perpendicular distance are same so turning force is depend on forces.
$∴$ T $_{A}$ : T $_{B}$ = 4:9
So Turning Force is greater in body B.