Two rods A and B are of equal lengths. Their ends are kept between the same temperature and their area of cross-sections are A1 and A2 and thermal conductivities K1 and K2. The rate of heat transmission in the two rods will be equal, if

K1A2 = K2A1

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K1A1 = K2A2

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K1 = K2

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Solution

The correct option is B
K1A1 = K2A2

${(\frac{Q}{t})}_{1} = \frac{K_{1} A_{1} (θ_{1} - θ_{2})}{l} a n d {(\frac{Q}{t})}_{2} = \frac{K_{2} A_{2} (θ_{1} - θ_{2})}{l}$

given ${(\frac{Q}{t})}_{1} = {(\frac{Q}{T})}_{2} \Rightarrow K_{1} A_{1} = K_{2} A_{2}$

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