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Question

Two rods made of different materials are placed between massive walls (see fig.). The cross-section of the rods is A and their respective lengths are l1and l2. The rods are heated through toC. Find the force with which the rods act on each other if their coefficients of expansion are α1 and α2 and their Young's moduli are E1 and E2. Neglect the deformation of the walls


A

F=Atl1α1+l2α2l1E1+l2E2

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B

F=Atl2α1+l1α2l1E1+l2E2

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C

F=Atl1α1+l2α2l1E2+l2E1

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D

F=Atl1α1+l2α2l2E1+l1E2

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Solution

The correct option is A

F=Atl1α1+l2α2l1E1+l2E2


Since there is no shift in the junction, the sum net elongation of both the rods should be zero.

The net elongation in each rod is equal to (elongation due to heating - contraction due to the force)

Therefore, if F is the force acting at the junction, we have

Δl1=l1α1tFl1E1A

Similarly

Δl2=l2α2tFl2E2A

The two elongations should add up to zero.

l1α1tFl1E1A+l2α2tFl2E2A=0

(l1α1+l2α2)t=FA(l1E1+l2E2)

F=Atl1α1+l2α2l1E1+l2E2


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