Two rods of the same length and areas of cross-section $A_{1}$ and $A_{2}$ have their ends at the same temperature. $K_{1}$ and $K_{2}$ are the thremal conductivities of the two rods. The rate of flow of heat is same in both rods if

\frac{A_{1}}{A_{2}} = \frac{K_{1}}{K_{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{A_{1}}{A_{2}} = \frac{K_{2}}{K_{1}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

A_{1} A_{2} = K_{1} K_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A_{1} K_{1}^{2} = A_{2} K_{2}^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{A_{1}}{A_{2}} = \frac{K_{2}}{K_{1}}$
If the rate of flow of heat is same in both rods, then
$\frac{K_{1} A_{1} (T_{2} - T_{1})}{l} = \frac{K_{2} A_{2} (T_{2} - T_{1})}{l} \frac{A_{1}}{A_{2}} = \frac{K_{2}}{K_{1}}$
option (B) is the correct answer

Suggest Corrections

Similar questions

Two different metal rods of the same length have their ends kept at the same temperatures $θ_{1}$ and $θ_{2}$ with $θ_{2}$ > $θ_{1}$ . If $A_{1}$ and $A_{2}$ are their cross-sectional areas and $k_{1}$ and $k_{2}$ their thermal conductivities, the rate of heat flow in the two rods will be same if

Q. Two rods

P

and

Q

have equal lengths. Their thermal conductivities are

K_{1}

and

K_{2}

and cross-sectional areas are

A_{1}

and

A_{2}

. When the temperature at ends of each rod are

T_{1}

and

T_{2}

respectively, the rate of flow of heat through

P

and

Q

will be equal, if

Two different metal rods of the same length their ends kept at the same temperatures $θ_{1}$ and $θ_{2}$ with $θ_{2}$ > $θ_{1}$ If $A_{1}$ and $A_{2}$ are their cross-sectional area and $K_{1}$ and $K_{2}$ their thermal conductivities, the rate of flow of heat in the two rods will be the same if

Join BYJU'S Learning Program

Two rods of the same length and areas of cross-section A1 and A2 have their ends at the same temperature. K1 and K2 are the thremal conductivities of the two rods. The rate of flow of heat is same in both rods if

The correct option is B A1A2=K2K1If the rate of flow of heat is same in both rods, thenK1A1(T2−T1)l=K2A2(T2−T1)lA1A2=K2K1option (B) is the correct answer

Two rods of the same length and areas of cross-section $A_{1}$ and $A_{2}$ have their ends at the same temperature. $K_{1}$ and $K_{2}$ are the thremal conductivities of the two rods. The rate of flow of heat is same in both rods if

The correct option is B $\frac{A_{1}}{A_{2}} = \frac{K_{2}}{K_{1}}$
If the rate of flow of heat is same in both rods, then
$\frac{K_{1} A_{1} (T_{2} - T_{1})}{l} = \frac{K_{2} A_{2} (T_{2} - T_{1})}{l} \frac{A_{1}}{A_{2}} = \frac{K_{2}}{K_{1}}$
option (B) is the correct answer