Two rods of the same weight and equal length have different thickness. They are held vertically on the surface of sand as shown in Figure. Which one of them will sink more? Why?

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both sink same

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cant say

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Solution

The correct option is C B
Pressure(P) $=$ $\frac{F o r c e (F)}{A r e a (A)}$
The rod A having more area of contact compared to rod B,and the forces is same because of same weight of the rods. Therefore the rod B will exert more pressure on that area than rod A. Hence,the rod B will sink more.

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Two rods of the same weight and equal length have different thickness. They are held vertically on the surface of sand as shown in Figure. Which one of them will sink more? Why?

The correct option is C BPressure(P)=Force(F)Area(A)The rod A having more area of contact compared to rod B,and the forces is same because of same weight of the rods. Therefore the rod B will exert more pressure on that area than rod A. Hence,the rod B will sink more.

The correct option is C B
Pressure(P) $=$ $\frac{F o r c e (F)}{A r e a (A)}$
The rod A having more area of contact compared to rod B,and the forces is same because of same weight of the rods. Therefore the rod B will exert more pressure on that area than rod A. Hence,the rod B will sink more.