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Question

Two rotating bodies A and B of masses m and 2m with moments of inertia IA and IB (IB > IA) have equal kinetic energy of rotation. If LA and LB be their angular momenta respectively, then

A
LB > LA
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B
LA > LB
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C
LA = LB2
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D
LA =2LB
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Solution

The correct option is A LB > LA
The kinetic energy of rotation is given by 12Iω2.
Since the kinetic energy of rotation is same,
IAω2A=IBω2B
ωAωB=IBIA
The ratio of the angular momentum becomes,
LALB=IAωAIBωB
=IAIB<1
LB>LA

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