The correct option is
C 2 m/s2The force is double and mass too is double,so cancels each other,and acceleration remain unchanged.
Let the force applied by two rubber bands is k Newton, mass of object be m kg.
F1=m1a1
a1=F1/m1
a1=k/m ..........eq1
Now, the force applied by four rubber bands would be 2k Newton.
Here mass too is twice i.e. 2mkg.
F2=m2a2
a2=F2/m2
a2=2k/2m=x/m .... eq2
a1=a2
from both equation we get that in both the
condition acceleration is same.
so in the condition of 2 rubber band the
acceleration is 2m/s²
then for the condition of four rubber band and
twice the mass,the acceleration must be 2m/s².
Hence,
option C is correct answer.