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Question

Two samples, each containing 400 g of water, are mixed. The temperature of sample A before mixing was 20C and that of sample B was 65C. What will be the final temperature of the mixture? (Specific heat of water = 4186 J/kg K)

A
22.5C
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B
42.5C
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C
32.5C
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D
52.5C
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Solution

The correct option is B 42.5C
Given:
Mass of sample A and B, mA=mB=400 g=0.4 kg
Temperature of sample A, TA=20C
Temperature of sample B, TB=65C
Specific heat of water, Sw=4186 J/kg K
The heat lost by sample A will be equal to heat gained by sample B.
Let the temperature of the mixture be Tm.
Heat lost = Heat gained
mASw(TBTm)=mBSw(TmTA)
0.4×(65Tm)=0.4×(Tm20)
2Tm=85
Tm=42.5C

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