wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two samples of gases ′a′ and ′b′ are at the same temperature. The molecules of ′a′ are travelling 4 times faster than molecules of ′b′. The ratio of Ma/Mb of their mass will be

A
1/4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
16/1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4/1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1/16
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C 1/16
Answer: D. 1/16

Given that molecules of 'a' are travelling 4 times faster than molecules of 'b'. That means rate of effusion of gas 'a' is 4 times than that of gas 'b'.

That is,
rarb=41 where, ra - rate of effusion of gas 'a' and rb - rate of effusion of gas 'b'.

According to Graham's Law of Effusion, for two gases 'a' and 'b' with molar masses Ma and Mb respectively ,

rarb=MbMa


Therefore, we can write as,

rarb=41=MbMa

=>MbMa=41

=>MbMa=161

=>MaMb=116

Therefore, option D. 1 / 16 is the correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Gas Laws
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon