Two satellites of masses $50 k g$ and $100 k g$ revolve around the earth in circular orbit of radii $9 R$ and $16 R$ respectively, where R is the radius of the earth. The speeds of the two satellites will be in the ratio

\frac{3}{4}

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\frac{4}{3}

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\frac{9}{16}

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\frac{16}{9}

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Solution

The correct option is B $\frac{4}{3}$
Orbital speed $v = \sqrt{\frac{G M}{R}}$ ; as we can see from the equation, it is independent of the mass of the satellite.
$G$ and $M$ are constants, hence
$\frac{v_{1}}{v_{2}} = \sqrt{\frac{R_{2}}{R_{1}}} = \sqrt{\frac{16}{9}} = 4 / 3$

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Two satellites of masses 50kg and 100kg revolve around the earth in circular orbit of radii 9R and 16R respectively, where R is the radius of the earth. The speeds of the two satellites will be in the ratio

The correct option is B 43Orbital speed v=√GMR ; as we can see from the equation, it is independent of the mass of the satellite.G and M are constants, hencev1v2=√R2R1=√169=4/3

Two satellites of masses $50 k g$ and $100 k g$ revolve around the earth in circular orbit of radii $9 R$ and $16 R$ respectively, where R is the radius of the earth. The speeds of the two satellites will be in the ratio

The correct option is B $\frac{4}{3}$
Orbital speed $v = \sqrt{\frac{G M}{R}}$ ; as we can see from the equation, it is independent of the mass of the satellite.
$G$ and $M$ are constants, hence
$\frac{v_{1}}{v_{2}} = \sqrt{\frac{R_{2}}{R_{1}}} = \sqrt{\frac{16}{9}} = 4 / 3$