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Question

Two schools A and B want to award their selected students on the values of sincerity, truthfulness and helpfulness. The school A wants to award ₹x each, ₹y each and ₹z each for the three respective values to 3, 2 and 1 students respectively with a total award money of ₹1,600. School B wants to spend ₹2,300 to award its 4, 1 and 3 students on the respective values (by giving the same award money to the three values as before). If the total amount of award for one prize on each value is ₹900, using matrices, find the award money for each value. Apart from these three values, suggest one more value which should be considered for award.

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Solution

Let the award money given for sincerity, truthfulness and helpfulness be ₹x, ₹y and ₹z respectively.

Since, the total cash award is ₹900.
∴ x + y + z = 900 ....(1)

Award money given by school A is ₹1,600.
∴ 3x + 2y + z = 1600 ....(2)

Award money given by school B is ₹2,300.
∴ 4x + y + 3z = 2300 ....(3)

The above system of equations can be written in matrix form CX = D as
111321413xyz=90016002300Where, C=111321413, X=xyz and D=90016002300Now,C=111321413 =16-1-19-4+1(3-8) =5-5-5 =-5Let Cij be the cofactors of elements cij in C=cij. Then,C11=-11+12113=5, C12=-11+23143=-5, C13=-11+33241=-5C21=-12+11113=-2 , C22=-12+2 1143=-1 , C23=-12+31141=3C31=-13+11121=-1, C32=-13+21131=2, C33=-13+31132=-1adj C= 5-5-5-2-1 3-1 2-1T = 5-2-1-5-1 2-5 3-1C-1=1Cadj C =1-5 5-2-1-5-1 2-5 3-1X=C-1Dxyz=-15 5-2-1-5-1 2-5 3-190016002300xyz=-154500-3200-2300-4500-1600+4600-4500+4800-2300xyz=-15-1000-1500-2000x=-1000-5, y=-1500-5 and z=-2000-5 x= 200, y= 300 and z=400.

Hence, the award money for each value of sincerity, truthfulness and helpfulness is ₹200, ₹300 and ₹400.

One more value which should be considered for award hardwork.

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