Two second sources produce progressive waves given by y1 - 12cos 100- t and y2 - 4cos 102- t neat the ear of an observer- When sounded together- the observer will hear-

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Question

Two second sources produce progressive waves given by $y_{1} = 12 cos 100 π t$ and $y_{2} = 4 cos 102 π t$ neat the ear of an observer. When sounded together, the observer will hear.

2

beats per two sound source with an intensity ratio of maximum to minimum nearly

4 : 1

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1

beat per second with an intensity ratio of maximum to minimum nearly

\sqrt{2} : 1

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1

beats per second with an intensity ratio of maximum to minimum nearly

9 : 1

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1

beat per second with an intensity ratio of maximum to minimum nearly

4 : 1

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Solution

The correct option is C $1$ beats per second with an intensity ratio of maximum to minimum nearly $9 : 1$
The frequency of the first wave is, $ν_{1} = 50$ Hz
The frequency of the second wave is, $ν_{2} = 51$ Hz
Number of beats per second $= 51 - 50 = 1$ hz
Intensity ratio $= \frac{12^{2}}{4^{2}} = \frac{144}{16} = \frac{9}{1} = 9 : 1$

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Two second sources produce progressive waves given by y1=12cos100πt and y2=4cos102πt neat the ear of an observer. When sounded together, the observer will hear.

The correct option is C 1 beats per second with an intensity ratio of maximum to minimum nearly 9:1The frequency of the first wave is, ν1=50HzThe frequency of the second wave is, ν2=51HzNumber of beats per second=51−50=1hzIntensity ratio=12242=14416=91=9:1

Two second sources produce progressive waves given by $y_{1} = 12 cos 100 π t$ and $y_{2} = 4 cos 102 π t$ neat the ear of an observer. When sounded together, the observer will hear.