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Two separate bulbs contain ideal gases A and B at the same temperature. The density of gas B is half of A while molar mass of gas B is twice of gas A. The ratio of pressure of A to that of B is:

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Solution

$P M = d R T$
For $A, P_{A} M_{A} = d_{A} . R T$
For $B, P_{B} 2 M_{A} = \frac{1}{2} d_{A} . R T$
$\frac{P_{A}}{P_{B}} = \frac{2 d_{A} . R T}{d_{A} . R T} \times \frac{2 M_{A}}{M_{A}} = 4$
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