Two sets A and B have p and q elements respectively. Then the number of relations from B to A is
A
p+q
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B
pq
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C
qp
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D
2pq
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Solution
The correct option is D2pq n(A)=pn(B)=qn(B×A)=pq
Any relation from B to A is a subset of (B×A). Number of subsets of B×A=2pq
Hence, there are 2pq relations from B to A.