Two sets A&B such that n(A)=p and n(B)=q, then the number of functions from A→B is , and from B→A is
A
2p+q
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B
pq
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C
qp
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D
2pq
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Solution
The correct option is Cqp Given two sets A&B such that n(A)=p&n(B)=q
We know that number of functions from A→B=n(B)n(A)=qp
Similarly, the number of functions from B→A=pq