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Question

Two shafts having same length and material are joined in series and subjected to a torque of 10 kN-m. If the ratio of their diameters is 2 : 1, then the ratio of their angles of twist is

A
16 : 1
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B
2 : 1
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C
1 : 2
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D
1 : 16
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Solution

The correct option is D 1 : 16
θ=TLGJ

θ1θ2=J2J1=(d2d1)4=116

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