Two ships are 10 km apart on a line joining south to north. The one farther north is steaming west at 20km h−1. The other is steaming north at 20km h−1. What is their distance of closest approach? How long do they take to reach it?
A
5√2 km,15 min
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B
10 km,12 min
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C
5√2 km,12 min
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D
5√2 km,10√2 min
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Solution
The correct option is A5√2 km,15 min
The velocity component of both ships 1 and 2 are equal. Hence, the angle between the two vectors is 45 degrees. Solving from the frame of particle - 1 We get dshort=10sin45∘=10√2=5√2 km t=10sin45|→v21|=10×1√220√2=14=15 min