wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two ships are 10 km apart on a line joining south to north. The one farther north is steaming west at 20 km h1. The other is steaming north at 20 km h1. What is their distance of closest approach? How long do they take to reach it?

A
52 km, 15 min
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
10 km, 12 min
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
52 km, 12 min
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
52 km, 102 min
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 52 km, 15 min

The velocity component of both ships 1 and 2 are equal. Hence, the angle between the two vectors is 45 degrees.
Solving from the frame of particle - 1
We get dshort=10sin45=102=52 km
t=10sin45|v21|=10×12202=14=15 min

flag
Suggest Corrections
thumbs-up
67
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Motion in 2D
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon