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Question

Two SHM are represented by equation x1=4 sin(ωt+37o) and x2=5 cos(ωt). The phase difference between them is

A
37o
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B
127o
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C
53o
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D
143o
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Solution

The correct option is C 53o

Given,

x=Asin(ωt+ϕ),

where,

A= Amplitude

ϕ= Phase Angle

x1=4 sin(ωt+37o)(1)

x2=5 cos (ωt)=5sin(ωt+90o)(2)

Phase angle difference is 90o37o=53o


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