Question

Two SHM are represented by $X_{1}a\sin (\omega t+{\alpha }_1)$ and $X_{2}a\sin (\omega t+{\alpha }_2)$ obtain the expression for displacement and amplitude.

Answer 1

Total energy of particle executing SHM is = 1/2 mw2A2

for 1 st particle E1 = 1/2 m (10)2(4)2

for 2nd particle E2 = 1/2 m (w)2(5)2

E1 =E2

so w = 10*4/5

=8