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Byju's Answer
Standard XII
Mathematics
Property 2
Two SHM's are...
Question
Two SHM's are represented by
x
1
=
a
1
s
i
n
(
ω
t
+
α
1
)
and
x
2
=
a
2
s
i
n
(
ω
t
+
α
2
)
. Obtain the expression for the displacement, amplitude and initial phase of the resultant motion.
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Solution
R
=
√
a
2
1
+
a
2
2
+
2
a
1
a
2
cos
(
α
1
−
α
2
)
ϕ
=
tan
−
1
[
a
1
sin
α
1
+
a
2
sin
α
2
a
1
cos
α
1
+
a
2
cos
α
2
]
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Similar questions
Q.
Two SHM are represented by
X
1
a
sin
(
ω
t
+
α
1
)
and
X
2
a
sin
(
ω
t
+
α
2
)
obtain the expression for displacement and amplitude.
Q.
A particle is subjected to two SHM's
X
1
=
a
1
sin
ω
t
and
X
2
=
a
2
sin
(
ω
t
+
ϕ
)
simultaneously where
a
1
=
3.0
c
m
,
a
2
=
4.0
c
m
. Find resultant amplitude if the phase difference
ϕ
has values
(a)
θ
∘
(b)
60
∘
(c)
90
∘
.
Q.
A particle is subjected to SHM
x
1
=
A
1
sin
ω
t
and
x
2
=
A
2
sin
(
ω
t
+
π
4
)
. The resultant SHM will have an amplitude of :
Q.
A particle is subjected to SHM as given by equations
x
1
=
A
1
sin
ω
t
and
x
2
=
A
2
sin
(
ω
t
+
π
/
3
)
.
The maximum acceleration and amplitude of the resultant motion
are
a
max
and
A
,
respectively, then
Q.
Let
a
1
and
a
2
be the amplitudes of two light waves of same frequency and
α
1
and
α
2
be their initial phases. The resultant amplitude due to the superposition of two light waves is
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