Question

Two $SH{M}^{\prime }s$ are represented by $y=a\sin (\omega t-kx)$ and $y=b\cos (\omega t-kx)$. The phase different between the two is

• A. $\pi /2$
• B. $\pi /4$
• C. $\pi /6$
• D. $3\pi /4$

Answer 1

The correct option is A $\pi /2$

Travelling wave equation is $y=a\sin (\omega t-kx)$

where $k=\frac{2\pi }{\lambda }$ and $\omega =\frac{2\pi }{T}$

$\lambda =$wave length

$T=$Period of oscillation

$y=a\sin (\omega t-kx)$ and

$y=b\sin (\omega t-kx+\frac{\pi }{2})$

$\therefore$ Phase difference$=(\omega t-kx+\frac{\pi }{2})-(\omega t-kx)=\omega t-kx+\frac{\pi }{2}-\omega t+kx=\frac{\pi }{2}$