Two short dipoles moment P are placed at two corners of a square as shown in the figure. What is the ratio of magnitudes of electric field at two points O and A?

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2 \sqrt{2}

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\sqrt{2}

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Solution

The correct option is B $2 \sqrt{2}$
$E_{r_{1}} = \frac{2 k p c o s 45^{0}}{r^{3}} = E_{r_{2}}$

$E_{0} = 2 E_{t} = \frac{\sqrt{2} k p}{(\frac{l}{\sqrt{2}})^{3}} = \frac{2 \sqrt{2}}{l^{3}} = \frac{\sqrt{k} p}{l^{3}}$

ratio = $2 \sqrt{2}$

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Two short dipoles moment P are placed at two corners of a square as shown in the figure. What is the ratio of magnitudes of electric field at two points O and A?

The correct option is B 2√2Er1=2kpcos450r3=Er2E0=2Et=√2kp(l√2)3=2√2l3=√kpl3ratio = 2√2

The correct option is B $2 \sqrt{2}$
$E_{r_{1}} = \frac{2 k p c o s 45^{0}}{r^{3}} = E_{r_{2}}$

$E_{0} = 2 E_{t} = \frac{\sqrt{2} k p}{(\frac{l}{\sqrt{2}})^{3}} = \frac{2 \sqrt{2}}{l^{3}} = \frac{\sqrt{k} p}{l^{3}}$

ratio = $2 \sqrt{2}$