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Question

Two short magnets each of moment M are placed one over the other at right angles. The resultant magnetic induction at a point P that lies at a distance d from the common centre is-



A
(μ04π)Md3
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B
(μ04π)3Md3
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C
3×(μ04π)Md3
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D
5×(μ04π)Md3

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Solution

The correct option is D 5×(μ04π)Md3

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}-->
As we can see, P is an equatorial and axial point with respect to magnet (1) and (2) respectively.



The resultant field at point P is,

BR=(Beq)21+(Bax)22

=(Beq)21+(2Beq)21 [Bax=2Beq]

=5(Beq)1

=5×(μ04π)Md3

Hence, (D) is the correct answer.

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