Two sides AB and BC and median AD of triangle ABC are respectively equalto sides PQ and QR and median PN of - PQR Then- - ABD- PQNIf the above statement is true then mention answer as 1- else mention 0 if false

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Byju's Answer

Standard VII

Mathematics

Equal Angles Subtend Equal Sides

Two sides AB ...

Question

Two sides AB and BC and median AD of triangle ABC are respectively equal
to sides PQ and QR and median PN of $Δ P Q R$ Then, $Δ A B D \equiv Δ P Q N$
If the above statement is true then mention answer as 1, else mention 0 if false

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Solution

Given $B C = Q R$
$\frac{1}{2} B C = \frac{1}{2} Q R$
$B D = Q N$
In $△$ ABD and PQN,
$A B = P Q$ (Given)
$B D = Q N$ (Proved above)
$A D = P N$ (Given)
Thus, $△ A B D ≅ △ P Q N$ (SSS rule)

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Similar questions

In the given figures, the sides AB and BC and the median AD of $Δ$ ABC are respectively equal to the sides PQ and QR and median PS of
$Δ$ PQR. Hence $Δ A B C$ and $Δ P Q R$ are right-angled triangles.

If the above statement is true then mention answer as 1, else mention 0 if false.

Q. Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of

Δ

PQR. Show that

Δ

ABM

≅

Δ

PQN

Q. Two sides

A B

and

B C

and median

A M

of one triangle

A B C

are respectively equal to side

P Q

and

Q R

and median

P N

Δ P Q R

(see figure). Show that
(i)

Δ A B M = Δ P Q N

(ii)

Δ A B C = Δ P Q R

Q. Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of ΔPQR (see the given figure). Show that:

Δ A B M ≅ Δ P Q N

Q. Two sides AB, BC and median AM of one triangle ABC are respectively.
equal to sides PQ and QR and median PN of ΔPQR (See figure)
(i) ΔABM ≅ ΔPQN
(ii) ΔABC ≅ ΔPQR

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Two sides AB and BC and median AD of triangle ABC are respectively equalto sides PQ and QR and median PN of ΔPQR Then, ΔABD≡ΔPQNIf the above statement is true then mention answer as 1, else mention 0 if false

Given BC=QR12BC=12QRBD=QNIn △ ABD and PQN,AB=PQ (Given)BD=QN (Proved above)AD=PN (Given)Thus, △ABD≅△PQN (SSS rule)

Two sides AB and BC and median AD of triangle ABC are respectively equal
to sides PQ and QR and median PN of $Δ P Q R$ Then, $Δ A B D \equiv Δ P Q N$
If the above statement is true then mention answer as 1, else mention 0 if false

Given $B C = Q R$
$\frac{1}{2} B C = \frac{1}{2} Q R$
$B D = Q N$
In $△$ ABD and PQN,
$A B = P Q$ (Given)
$B D = Q N$ (Proved above)
$A D = P N$ (Given)
Thus, $△ A B D ≅ △ P Q N$ (SSS rule)