Question

Two sides of a triangle are 6-4 m and 4-8 m. If height of the triangle corresponding to 4-8 m side id 6 m; find:

(i) Area of the triangle;

(ii) Height of the triangle corresponding to 6-4 m side

Answer 1

ABC is the $\Delta$ in which BC =4.8 m

AC=6.4 m and AD =6 m

$\therefore$ area of $\Delta ABC=\frac{1}{2}BC\times AD$

$=\frac{1}{2}\times 4.8\times 6$

$=14.4m^2$

BE is height of $\Delta$ corresponding to 6.4 m

$\therefore \frac{1}{2}AC\times BE=14.4$

$\frac{1}{2}\times 6.4\times BE=14.4$

$BE=\frac{14.4\times 2}{6.4}$

$BE=\frac{14.4}{3.2}$

$=\frac{9}{2}=4.5m$

Hence, (i)14.4 $m^2$ (ii)4.5 m