Two similar rods are joined as shown in figure, then temperature of junction is (assume no heat loss through lateral surface of rod and temperatures at the ends are shown in steady state condition)
A
50∘C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
75∘C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
66.6∘C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
33.3∘C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A50∘C
At junction, incoming heat will be same as outgoing heat. Let, T be the temperature at junction and R be the thermal resistance. So, H=H1+H2+H3 100−TR=50−0R+T−50R+T−50R ⇒100−T=2T−50 ⇒3T=150∴T=50∘C