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Question

# Two similar very small conducting spheres having charges 40C and −20C are at some distance apart. Now they are touched and then kept at a same initial distance. The ratio of the initial to the final force between them is:

A
8:1
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B
4:1
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C
1:8
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D
1:1
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Solution

## The correct option is A 8:1Initially force between conducting spheres F1=Kq1q2r2=K(40)(−20)r2(i)After contact total charge=40−20=20μCNow charge will be equally distributedso q1=q2=202=10μCFinally force between spheresF2=K(10)(10)r2(ii)Ratio of forces=F1F2=40×2010×10=8

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