Two simple harmonic motions are represented by equations, y1=4sin(10t+ϕ) and y2=5cos10t. What is the phase difference between their velocities?
A
ϕ
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B
−ϕ
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C
ϕ+π2
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D
ϕ−π2
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Solution
The correct option is Dϕ−π2 Given that, y1=4sin(10t+ϕ) y2=5cos10t
The velocity is given by v1=ddt(4sin(10t+ϕ)) ⇒v1=40cos(10t+ϕ)
and v2=ddt(5cos10t) ⇒v2=−50sin10t
The phase difference between v1 and v2 is Δϕ=(10t+ϕ)−(10t+π2) ⇒Δϕ=ϕ−π2