Two simple harmonic motions are represented by the equations- y1 - 10 sin -4 12 t - I- y2 - 5 sin 3 pt - -3 cos 3 ptThe ratio of their amplitudes is

The correct option is C 1 : 1 y_1 = 10 sin π/4 (12 t + I), #160; #160; #160; #160; (amp)_1=10 y_2 = 5 (sin 3 pt + √(3) cos 3 pt) ...

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Two simple ha...

Question

Two simple harmonic motions are represented by the equations.
$y_{1} = 10 s i n \frac{π}{4} (12 t + I), y_{2} = 5 (s i n 3 p t + \sqrt{3} c o s 3 p t)$
The ratio of their amplitudes is

1 : 1

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1 : 2

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3 : 2

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2 : 3

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y_{1} = 10 sin \frac{π}{4} (12 t + 1), y_{2} = 5 (((sin 3 p t + \sqrt{3} cos 3 p t)

Y_{1} = 10 sin (3 π t + \frac{π}{4})

Y_{2} = 5 (sin 3 π t + \sqrt{3} cos 3 π t)

y_{1} = 10 sin (3 π t + π / 4)

y_{2} = 5 (sin 3 π t + \sqrt{3} cos 3 π t)

y_{1} = 5 sin (\begin{matrix} 2 π t + \frac{π}{4} \end{matrix})

y_{2} = 2 \sqrt{2} (sin 2 π t + cos 1 π t)

y_{1} = 10 s i n (3 π t + \frac{π}{4}), y_{2} = 5 (s i n 3 π t + \sqrt{3} s i n 3 π t)

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