Two sine waves travel in the same direction in a medium. The amplitude of each wave is A and the phase difference between the two waves is 120 $^{\circ}$ . The resultant amplitude will be

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$\sqrt{2} A$

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Solution

The correct option is A A
$A_{1} = A_{2}$

$A_{n e t} = \sqrt{A^{2} + A^{2} + 2 A^{2} c o s 120^{\circ}}$

$A_{n e t} = A$

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Two sine waves travel in the same direction in a medium. The amplitude of each wave is A and the phase difference between the two waves is 120∘. The resultant amplitude will be

The correct option is A AA1=A2 Anet=√A2+A2+2A2cos120∘ Anet=A

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$A_{n e t} = A$