Two skaters A and B of mass 50 kg and 70 kg respectively stand facing each other 6 m apart. Then they pull a rope stretched between them. How far has each moved when they meet?
A
A moves 3.5 m and B 2.5m
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B
A moves 2 m and B 4m
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C
both have moved 3 m
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D
both have moved 2.5 m
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Solution
The correct option is A A moves 3.5 m and B 2.5m Since force applied on both the should be equal and opposite, ∴m1a1=m2a2 i.e. m1s1=m2s2 Also, s1+s2=6 ∴50×s1=70×s2 ∴50×s1=70×(6−s2) ∴s1=3.5 m