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Question

Two skaters A and B of mass 50 kg and 70 kg respectively stand facing each other 6 metres apart. They then pull on a light rope stretched between them. How far has each moved when they meet?

A
Both have moved 3 metres
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B
A moves 2.5 metres and B moves 3.5 metres.
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C
A moves 3.5 metres and B moves 2.5 metres.
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D
A moves 2 metres and B moves 4 metres.
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Solution

The correct option is C A moves 3.5 metres and B moves 2.5 metres.

Here no any external force is applied taking two stakers A and B as a system.
then center of mass of both stakers will not change therefore they meat at center of mass, taking axis as shown in figure 1.
Xcom=50×0+70×650+70=70×6120=3.5m from 50kg sketers.
Xcom = X-coordinate of center of mass.
So A mover 3.5cm
B mover (6 - 3.5) = 2.5m
Option C-correct

949130_366323_ans_9a13cd58ade34acd947264ca74c86dd2.jpg

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